I had to take a DateTime in the format of 2009-10-23 00:00:00 and convert it to 10/23/2009 using XSL. XSL 1.0 doesn’t have any type of datetime formatting functions, so the following snippet should help anyone else in a similar predicament:
<xsl:element name="newdate">
<xsl:call-template name="FormatDate">
<xsl:with-param name="DateTime" select="@Date"/>
</xsl:call-template>
</xsl:element>
…
<xsl:template name="FormatDate">
<xsl:param name="DateTime" />
<xsl:variable name="Year">
<xsl:value-of select='substring-before($DateTime,"-")'/>
</xsl:variable>
<xsl:variable name="NoYear">
<xsl:value-of select='substring-after($DateTime,"-")'/>
</xsl:variable>
<xsl:variable name="Month">
<xsl:value-of select='substring-before($NoYear,"-")'/>
</xsl:variable>
<xsl:variable name="DayWithTime">
<xsl:value-of select='substring-after($NoYear,"-")'/>
</xsl:variable>
<xsl:variable name="Day">
<xsl:value-of select='substring-before($DayWithTime," ")'/>
</xsl:variable>
<xsl:value-of select='$Month'/>
<xsl:text>/</xsl:text>
<xsl:value-of select='$Day'/>
<xsl:text>/</xsl:text>
<xsl:value-of select='$Year'/>
</xsl:template>